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0=-16x^2+65x+361
We move all terms to the left:
0-(-16x^2+65x+361)=0
We add all the numbers together, and all the variables
-(-16x^2+65x+361)=0
We get rid of parentheses
16x^2-65x-361=0
a = 16; b = -65; c = -361;
Δ = b2-4ac
Δ = -652-4·16·(-361)
Δ = 27329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-\sqrt{27329}}{2*16}=\frac{65-\sqrt{27329}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+\sqrt{27329}}{2*16}=\frac{65+\sqrt{27329}}{32} $
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